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In the question it is asked how many recombinant daughter chromosomes and genetically distinct daughter chromosomes are present after Meiosis. I picked answer C (row 5), since 4 daughter chromosomes are obviously correct, but since those 4 originate from recombinant chromosomes, I thought that they are also all recombinant.
Is the answer in the diagram? So do only the right chromatid of the left chromosome (abd) and the left of the right chromosome (ABD) cross over, and so there are only 2 recombinant chromatids/daughter chromosomes? So in this case the recombinant chromosomes would be aBD and Abd (crossing over site between Aa and Bb/Dd parts)?
And if yes, are there cases in which all 4 chromatids are crossing over / are recombinant after Meiosis?
Thanks in advance!
A recombinant chromosome specifically means a chromosome that has received DNA from the other homolog through crossing over. Simply being produced by meiosis does not make it recombinant.
There are 4 daughter chromosomes in total at the end of meiosis, these are ABD, abd, Abd, and aBD.
But only 2 are recombinant, these are Abd and aBD.